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Nitto Open Semi-final 2021 Head to Head Prediction: Novak Djokovic vs Alexander Zverev

The Nitto ATP finals 2021, semifinal will see Novak Djokovic go head to head against Alexander Zverev at the Centre Court Pala to fight for the final spot on Saturday night.  

Novak Djokovic vs Alexander Zverev: Head to Head Preview

Djokovic has been the most successful player in Tennis. In his two years, he has been flawless and is ticking every box to claim his status as one of the greatest players in Tennis. 

Djokovic has been up against one of the finest tennis players, and there is no question that his statistics are the same as Federer and Nadal. 

After his loss at the Tokyo Olympics against Zverev, Djokovic will be determined to avenge his defeat and will be optimistic going into this match. 

Sascha Zverev stole the spotlight when he routed the Serbian in the 2021 Tokyo Olympics. Since then, he has been most talked about in Tennis. 

The German is the most consistent player this season after Djokovic. He has played three grand slams semifinals and has two master’s titles and an Olympic gold medal.

Novak Djokovic vs Alexander Zverev: Head-to-head Record

Djokovic Wins8
Zverev Wins3

Both the stars will meet for the 12th time today. Djokovic is the favourite in this head-to-head fixture, winning eight matches while Zverev has triumphed in 3. 

Most recently, they played on September 10, 2021, with Serbian winning 3-2 (4-6, 6-2, 6-4, 4-6, 6-2) in the 2021 US Open Semi-Finals.  

Novak Djokovic vs Alexander Zverev: Head to Head Form Guide

DjokovicWWWWW
ZverevWLWLW

Novak Djokovic vs Alexander Zverev: Prediction 

This will be an action-packed game between the two tennis stars. The contest is expected to be a cracker, and will most probably go down the distance.  

This will be a long game as both the players will eye the final spot. A lot of long rallies are expected, and Djokovic will be facing Zverev’s fire severs. However, Djokovic has enough experience and composure to edge past Zverev.

Prediction: Djokovic to win in three sets.

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